(7v^2+4v+6)(2v-5)=

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Solution for (7v^2+4v+6)(2v-5)= equation: 


Simplifying
(7v2 + 4v + 6)(2v + -5) = 0

Reorder the terms:
(6 + 4v + 7v2)(2v + -5) = 0

Reorder the terms:
(6 + 4v + 7v2)(-5 + 2v) = 0

Multiply (6 + 4v + 7v2) * (-5 + 2v)
(6(-5 + 2v) + 4v * (-5 + 2v) + 7v2 * (-5 + 2v)) = 0
((-5 * 6 + 2v * 6) + 4v * (-5 + 2v) + 7v2 * (-5 + 2v)) = 0
((-30 + 12v) + 4v * (-5 + 2v) + 7v2 * (-5 + 2v)) = 0
(-30 + 12v + (-5 * 4v + 2v * 4v) + 7v2 * (-5 + 2v)) = 0
(-30 + 12v + (-20v + 8v2) + 7v2 * (-5 + 2v)) = 0
(-30 + 12v + -20v + 8v2 + (-5 * 7v2 + 2v * 7v2)) = 0
(-30 + 12v + -20v + 8v2 + (-35v2 + 14v3)) = 0

Combine like terms: 12v + -20v = -8v
(-30 + -8v + 8v2 + -35v2 + 14v3) = 0

Combine like terms: 8v2 + -35v2 = -27v2
(-30 + -8v + -27v2 + 14v3) = 0

Solving
-30 + -8v + -27v2 + 14v3 = 0

Solving for variable 'v'.

The solution to this equation could not be determined.

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